3.171 \(\int \frac {\log (2 (3+e x^n))}{x} \, dx\)

Optimal. Leaf size=21 \[ \log (6) \log (x)-\frac {\text {Li}_2\left (-\frac {e x^n}{3}\right )}{n} \]

[Out]

ln(6)*ln(x)-polylog(2,-1/3*e*x^n)/n

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Rubi [A]  time = 0.03, antiderivative size = 21, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.214, Rules used = {2454, 2392, 2391} \[ \log (6) \log (x)-\frac {\text {PolyLog}\left (2,-\frac {e x^n}{3}\right )}{n} \]

Antiderivative was successfully verified.

[In]

Int[Log[2*(3 + e*x^n)]/x,x]

[Out]

Log[6]*Log[x] - PolyLog[2, -(e*x^n)/3]/n

Rule 2391

Int[Log[(c_.)*((d_) + (e_.)*(x_)^(n_.))]/(x_), x_Symbol] :> -Simp[PolyLog[2, -(c*e*x^n)]/n, x] /; FreeQ[{c, d,
e, n}, x] && EqQ[c*d, 1]

Rule 2392

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))]*(b_.))/(x_), x_Symbol] :> Simp[(a + b*Log[c*d])*Log[x], x] + Dist[
b, Int[Log[1 + (e*x)/d]/x, x], x] /; FreeQ[{a, b, c, d, e}, x] && GtQ[c*d, 0]

Rule 2454

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_)^(n_))^(p_.)]*(b_.))^(q_.)*(x_)^(m_.), x_Symbol] :> Dist[1/n, Subst[I
nt[x^(Simplify[(m + 1)/n] - 1)*(a + b*Log[c*(d + e*x)^p])^q, x], x, x^n], x] /; FreeQ[{a, b, c, d, e, m, n, p,
q}, x] && IntegerQ[Simplify[(m + 1)/n]] && (GtQ[(m + 1)/n, 0] || IGtQ[q, 0]) &&  !(EqQ[q, 1] && ILtQ[n, 0] &&
IGtQ[m, 0])

Rubi steps

\begin {align*} \int \frac {\log \left (2 \left (3+e x^n\right )\right )}{x} \, dx &=\frac {\operatorname {Subst}\left (\int \frac {\log (2 (3+e x))}{x} \, dx,x,x^n\right )}{n}\\ &=\log (6) \log (x)+\frac {\operatorname {Subst}\left (\int \frac {\log \left (1+\frac {e x}{3}\right )}{x} \, dx,x,x^n\right )}{n}\\ &=\log (6) \log (x)-\frac {\text {Li}_2\left (-\frac {e x^n}{3}\right )}{n}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 21, normalized size = 1.00 \[ \log (6) \log (x)-\frac {\text {Li}_2\left (-\frac {e x^n}{3}\right )}{n} \]

Antiderivative was successfully verified.

[In]

Integrate[Log[2*(3 + e*x^n)]/x,x]

[Out]

Log[6]*Log[x] - PolyLog[2, -1/3*(e*x^n)]/n

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fricas [B]  time = 0.43, size = 41, normalized size = 1.95 \[ \frac {n \log \left (2 \, e x^{n} + 6\right ) \log \relax (x) - n \log \left (\frac {1}{3} \, e x^{n} + 1\right ) \log \relax (x) - {\rm Li}_2\left (-\frac {1}{3} \, e x^{n}\right )}{n} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(6+2*e*x^n)/x,x, algorithm="fricas")

[Out]

(n*log(2*e*x^n + 6)*log(x) - n*log(1/3*e*x^n + 1)*log(x) - dilog(-1/3*e*x^n))/n

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\log \left (2 \, e x^{n} + 6\right )}{x}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(6+2*e*x^n)/x,x, algorithm="giac")

[Out]

integrate(log(2*e*x^n + 6)/x, x)

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maple [B]  time = 0.07, size = 57, normalized size = 2.71 \[ \frac {\ln \left (-\frac {e \,x^{n}}{3}\right ) \ln \left (2 e \,x^{n}+6\right )}{n}-\frac {\ln \left (-\frac {e \,x^{n}}{3}\right ) \ln \left (\frac {e \,x^{n}}{3}+1\right )}{n}-\frac {\dilog \left (\frac {e \,x^{n}}{3}+1\right )}{n} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(ln(6+2*e*x^n)/x,x)

[Out]

-1/n*ln(-1/3*e*x^n)*ln(1/3*e*x^n+1)+1/n*ln(-1/3*e*x^n)*ln(6+2*e*x^n)-1/n*dilog(1/3*e*x^n+1)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ -\frac {1}{2} \, n \log \relax (x)^{2} + 3 \, n \int \frac {\log \relax (x)}{e x x^{n} + 3 \, x}\,{d x} + \log \relax (2) \log \relax (x) + \log \left (e x^{n} + 3\right ) \log \relax (x) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(6+2*e*x^n)/x,x, algorithm="maxima")

[Out]

-1/2*n*log(x)^2 + 3*n*integrate(log(x)/(e*x*x^n + 3*x), x) + log(2)*log(x) + log(e*x^n + 3)*log(x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.05 \[ \int \frac {\ln \left (2\,e\,x^n+6\right )}{x} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(log(2*e*x^n + 6)/x,x)

[Out]

int(log(2*e*x^n + 6)/x, x)

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sympy [C]  time = 3.87, size = 78, normalized size = 3.71 \[ \begin {cases} \log {\relax (6 )} \log {\relax (x )} - \frac {\operatorname {Li}_{2}\left (\frac {e x^{n} e^{i \pi }}{3}\right )}{n} & \text {for}\: \left |{x}\right | < 1 \\- \log {\relax (6 )} \log {\left (\frac {1}{x} \right )} - \frac {\operatorname {Li}_{2}\left (\frac {e x^{n} e^{i \pi }}{3}\right )}{n} & \text {for}\: \frac {1}{\left |{x}\right |} < 1 \\- {G_{2, 2}^{2, 0}\left (\begin {matrix} & 1, 1 \\0, 0 & \end {matrix} \middle | {x} \right )} \log {\relax (6 )} + {G_{2, 2}^{0, 2}\left (\begin {matrix} 1, 1 & \\ & 0, 0 \end {matrix} \middle | {x} \right )} \log {\relax (6 )} - \frac {\operatorname {Li}_{2}\left (\frac {e x^{n} e^{i \pi }}{3}\right )}{n} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(ln(6+2*e*x**n)/x,x)

[Out]

Piecewise((log(6)*log(x) - polylog(2, e*x**n*exp_polar(I*pi)/3)/n, Abs(x) < 1), (-log(6)*log(1/x) - polylog(2,
e*x**n*exp_polar(I*pi)/3)/n, 1/Abs(x) < 1), (-meijerg(((), (1, 1)), ((0, 0), ()), x)*log(6) + meijerg(((1, 1)
, ()), ((), (0, 0)), x)*log(6) - polylog(2, e*x**n*exp_polar(I*pi)/3)/n, True))

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